In polar coordinates we have r = sin(Q) cos(Q2) In cartesian coordiantes we get (x2+y2)2 = 4x2y.
The slope of the trajectory is . We get horizontal tangents for Q = 0, P/4, -P/4, and vertical tangents for Q = P/6, P/2, 5P/6.
The length of the trajectory is , again rather difficult to integrate.
The area enclosed by the trajectory is
= sin(Q)cos(Q)5/12 + sin(Q)cos(Q)3/48 + sin(Q)cos(Q)/32 + Q/32 = P/16 = 0.1963