a) Ann has 3 information sets: The one where she walks or stays,
the one where she decides between Lugano and Milano,
and the one where she chooses between green, blue, or red.
Since she has 2 options in the first, 2 option in the second, and 3 options in the third,
she has 2·2·3=12 pure strategies.
They are (walk,Lugano,green), (walk,Lugano,blue), (walk,Lugano,red),
(walk,Milano,green), (walk,Milano,blue), (walk,Milano,red),
(stay,Lugano,green), (stay,Lugano,blue), (stay,Lugano,red),
(stay,Milano,green), (stay,Milano,blue), (stay,Milano,red).
Beth has two information sets, the one where she calls or doesn't, and the one where she chooses
between high, middle or low. Since she has 2 options in the first case and 3 options in the other,
she has 2·3=6 pure strategies. They are (call,high), (call,middle), (call,low),
(don't,high), (don't,middle), (don't,low).
b) If Ann decides to stay, then she will not face the green/blue/red decision.
therefore we have reduced pure strategies (stay,Lugano,.) and (stay,Milano,.).
If Ann decides to walk, all other decisions may occur, so there are still the 5
reduced pure strategies (walk,Lugano,green), (walk,Lugano,blue), (walk,Lugano,red),
(walk,Milano,green), (walk,Milano,blue), (walk,Milano,red).
Thus Ann has 8 reduced pure strategies.
I select (walk,Lugano,green) and (stay,Lugano,blue) for Ann, and
(call,high) and (don't,middle) for Beth.
There are also four cases how Nature could play: "snow" with probability 1/3,
"warm" or "cold" "rain" with probability (1/3)·(1/2) = 1/6 each,
and "sun" with probability 1/3.
- If Ann plays (walk,Lugano,green) and Beth plays (call,high), then
the payoffs for Ann and Beth are 4, 1 provided Nature plays "snow",
1, 2 provided Nature plays "warm rain", 3, 1 if Nature plays "cold rain",
and 2, 3 if Nature plays "sun". Therefore the
expected payoff for Ann equals (1/3)·4 + (1/6)·1 + (1/6)·3 + (1/3)·2 = 8/3.
The expected payoff for Beth equals (1/3)·1 + (1/6)·2 + (1/6)·1 + (1/3)·3 = 11/6.
- If Ann plays (walk,Lugano,green) and Beth plays (don't,middle), then
the payoffs for Ann and Beth are 1, 4 provided Nature plays "snow",
1, 2 provided Nature plays "warm rain", 3, 1 if Nature plays "cold rain",
and 3, 1 if Nature plays "sun". Therefore the
expected payoff for Ann equals (1/3)·1 + (1/6)·1 + (1/6)·3 + (1/3)·3 = 2.
The expected payoff for Beth equals (1/3)·4 + (1/6)·2 + (1/6)·1 + (1/3)·1 = 13/6.
- If Ann plays (stay,Lugano,blue) and Beth plays (call,high), then
the payoffs for Ann and Beth are 3, 1 provided Nature plays "snow",
2, 1 provided Nature plays "warm rain", 2, 1 if Nature plays "cold rain",
and 2, 3 if Nature plays "sun". Therefore the
expected payoff for Ann equals (1/3)·3 + (1/6)·2 + (1/6)·2 + (1/3)·2 = 7/3.
The expected payoff for Beth equals (1/3)·1 + (1/6)·1 + (1/6)·1 + (1/3)·3 = 5/3.
- If Ann plays (stay,Lugano,blue) and Beth plays (don't,middle), then
the payoffs for Ann and Beth are 2, 1 provided Nature plays "snow",
2, 1 provided Nature plays "warm rain", 2, 1 if Nature plays "cold rain",
and 3, 1 if Nature plays "sun". Therefore the
expected payoff for Ann equals (1/3)·2 + (1/6)·2 + (1/6)·2 + (1/3)·3 = 7/3.
The expected payoff for Beth equals (1/3)·1 + (1/6)·1 + (1/6)·1 + (1/3)·1 = 1.